Ideal gas partition function: Difference between revisions

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[[Canonical ensemble]] partition function, ''Q'',
The [[canonical ensemble]] [[partition function]], ''Q'',
for a system of ''N'' identical particles each of mass ''m''
for a system of ''N'' identical particles each of mass ''m'' is given by


:<math>Q_{NVT}=\frac{1}{N!}\frac{1}{h^{3N}}\int\int dp^N dr^N \exp \left[ - \frac{H(p^N, r^N)}{k_B T}\right]</math>
:<math>Q_{NVT}=\frac{1}{N!}\frac{1}{h^{3N}}\int\int dp^N dr^N \exp \left[ - \frac{H(p^N, r^N)}{k_B T}\right]</math>
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:<math>Z_{NVT}= \int  dr^N  \exp \left[ - \frac{V(r^N)} {k_B T}\right]</math>
:<math>Z_{NVT}= \int  dr^N  \exp \left[ - \frac{V(r^N)} {k_B T}\right]</math>


In an ideal gas there are no interactions between particles so <math>V(r^N)=0</math>
In an [[ideal gas]] there are no interactions between particles so <math>V(r^N)=0</math>
Thus <math>\exp(-V(r^N)/k_B T)=1</math> for every gas particle.
Thus <math>\exp(-V(r^N)/k_B T)=1</math> for every gas particle.
The integral of 1 over the coordinates of each atom is equal to the volume so for ''N'' particles
The integral of 1 over the coordinates of each atom is equal to the volume so for ''N'' particles

Revision as of 16:50, 22 May 2007

The canonical ensemble partition function, Q, for a system of N identical particles each of mass m is given by

QNVT=1N!1h3N∫∫dpNdrNexp[−H(pN,rN)kBT]

When the particles are distinguishable then the factor N! disappears. H(pN,rN) is the Hamiltonian (Sir William Rowan Hamilton 1805-1865 Ireland) corresponding to the total energy of the system. H is a function of the 3N positions and 3N momenta of the particles in the system. The Hamiltonian can be written as the sum of the kinetic and the potential energies of the system as follows

H(pN,rN)=∑i=1N|pi|22m+V(rN)

Thus we have

QNVT=1N!1h3N∫dpNexp[−|pi|22mkBT]∫drNexp[−V(rN)kBT]

This separation is only possible if V(rN) is independent of velocity (as is generally the case). The momentum integral can be solved analytically:

∫dpNexp[−|p|22mkBT]=(2πmkbT)3N/2

Thus we have

QNVT=1N!1h3N(2πmkBT)3N/2∫drNexp[−V(rN)kBT]


The integral over positions is known as the configuration integral, ZNVT

ZNVT=∫drNexp[−V(rN)kBT]

In an ideal gas there are no interactions between particles so V(rN)=0 Thus exp(−V(rN)/kBT)=1 for every gas particle. The integral of 1 over the coordinates of each atom is equal to the volume so for N particles the configuration integral is given by VN where V is the volume. Thus we have

QNVT=VNN!(2πmkBTh2)3N/2

If we define the de Broglie thermal wavelength as Λ where

Λ=h2/2πmkBT

one arrives at

QNVT=1N!(VΛ3)N=qNN!

where

q=VΛ3

is the single particle translational partition function.


Thus one can now write the partition function for a real system can be built up from the contribution of the ideal system (the momenta) and a contribution due to particle interactions, i.e.

QNVT=QNVTidealQNVTexcess