Joule-Thomson effect: Difference between revisions
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In terms of the [[second virial coefficient]] one has | In terms of the [[second virial coefficient]] at zero [[pressure]] one has | ||
:<math>\mu_{\mathrm JT} = B_2 -T \frac{dB_2}{dT}</math> | :<math>\mu_{\mathrm JT} = B_2 -T \frac{dB_2}{dT}</math> | ||
Revision as of 12:17, 12 July 2007
The Joule-Thomson effect is also known as the Joule-Kelvin effect.
Joule-Thomson coefficient
The Joule-Thomson coefficient is given by
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu_{\mathrm JT} = \left. \frac{\partial T}{\partial p} \right\vert_H}
where T is the temperature, p is the pressure and H is the enthalpy.
In terms of heat capacities one has
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu_{\mathrm JT} C_V = -\left. \frac{\partial E}{\partial V} \right\vert_T }
and
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu_{\mathrm JT} C_p = -\left. \frac{\partial H}{\partial p} \right\vert_T }
In terms of the second virial coefficient at zero pressure one has
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu_{\mathrm JT} = B_2 -T \frac{dB_2}{dT}}