Integration of the kinetic degrees of freedom
Considering a system of  identical particles, with total energy
 identical particles, with total energy  given by:
 given by:
 
where the first term on the right hand side is the kinetic energy, whereas the second one is
the potential energy (function of the position coordinates)
Let  be the total energy of the system.
 be the total energy of the system.
The probability,  of a given position configuratiom
  of a given position configuratiom  , with potential energy
, with potential energy
 can be written as:
 can be written as:
![{\displaystyle \Pi \left(X^{3N}|E\right)\propto \int dP^{3N}\delta \left[K(P^{3N})-\Delta E\right]}](https://wikimedia.org/api/rest_v1/media/math/render/svg/7a4f2b8463932fb289d4087b0d19a79e9a1c97bd) ;   (Eq. 1) ;   (Eq. 1)
where  stands for the 3N momenta, and
 stands for the 3N momenta, and
 
The Integral in the right hand side of Eq. 1 corresponds to the surface of a 3N-dimensional hyper-sphere of radious 
 ;
Therefore:
 ;
Therefore:
![{\displaystyle \Pi \left(X^{3N}|E\right)\propto \left[E-U(X^{3N})\right]^{3N-1}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/169a5b43bfebff44df478684d8a81e41787d6a20) 
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