Talk:8-6 Lennard-Jones potential

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The formula given here should show rm rather than sigma as the numerator above r, as given in the cited source material. Using the formula shown, the potential does not equal zero when r=sigma; rather the derivative of the potential (i.e. the force) equals zero.

You are quite right. I have now corrected the equation given. Many thanks. -- Carl McBride (talk) 13:34, 2 June 2011 (CEST)
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