Talk:8-6 Lennard-Jones potential: Difference between revisions
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(Created page with "The formula given here should show rm rather than sigma as the numerator above r, as given in the cited source material. Using the formula shown, the potential does not equal zer...") |
Carl McBride (talk | contribs) (Reply) |
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The formula given here should show rm rather than sigma as the numerator above r, as given in the cited source material. Using the formula shown, the potential does not equal zero when r=sigma; rather the derivative of the potential (i.e. the force) equals zero. | The formula given here should show rm rather than sigma as the numerator above r, as given in the cited source material. Using the formula shown, the potential does not equal zero when r=sigma; rather the derivative of the potential (i.e. the force) equals zero. | ||
:You are quite right. I have now corrected the equation given. Many thanks. --[[User:Carl McBride | <b><FONT COLOR="#8B3A3A">Carl McBride</FONT></b>]] ([[User_talk:Carl_McBride |talk]]) 13:34, 2 June 2011 (CEST) | |||
Latest revision as of 12:34, 2 June 2011
The formula given here should show rm rather than sigma as the numerator above r, as given in the cited source material. Using the formula shown, the potential does not equal zero when r=sigma; rather the derivative of the potential (i.e. the force) equals zero.
- You are quite right. I have now corrected the equation given. Many thanks. -- Carl McBride (talk) 13:34, 2 June 2011 (CEST)